e^{x+1}=8^{x+8}

Lösung

e^{x + 1} = 8^{x + 8}

x = \frac{24 ln ( 2 ) - 1}{1 - 3 ln ( 2 )}

Dezimale

x = - 14.48483 \dots

Schritte zur Lösung

e^{x + 1} = 8^{x + 8}

Wende Exponentenregel an

x + 1 = (x + 8) ln (8)

Löse

x + 1 = (x + 8) ln (8) : x = \frac{24 ln ( 2 ) - 1}{1 - 3 ln ( 2 )}

x = \frac{24 ln ( 2 ) - 1}{1 - 3 ln ( 2 )}

4^{2 x} + 1 = 17

e^{2 x - 1} = e^{4}

\frac{1}{4} = 1 6^{2 x - 5}

4^{2 x + 1} = 8^{3 x + 4}

so l v e f or x, x = e^{- t}