(1/9)^{x-5}=3^{3x}

Lösung

(\frac{1}{9})^{x - 5} = 3^{3 x}

x = 2

Schritte zur Lösung

(\frac{1}{9})^{x - 5} = 3^{3 x}

Wende Exponentenregel an

- 2 (x - 5) = 3 x

Löse

- 2 (x - 5) = 3 x : x = 2

x = 2

4^{x - x^{2}} = \frac{1}{1 6 ^{x}}

4^{x + 2} + 4^{x - 1} = \frac{65}{64}

9^{x - 2} = 27

4^{3 x - 1} = 3 2^{- 4}

5^{x} = 8^{x}