What is the answer to 4\times 5^{x+1}-5=35 ?

The answer to 4\times 5^{x+1}-5=35 is x=(ln(10))/(ln(5))-1

Solve for x: 4\times 5^{x+1}-5=35

The solution is x=(ln(10))/(ln(5))-1

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4 \cdot 5^{x + 1} - 5 = 35

x = \frac{ln ( 10 )}{ln ( 5 )} - 1

Decimal Notation

x = 0.43067 \dots

Solution steps

4 \cdot 5^{x + 1} - 5 = 35

Move

5

to the right side

4 \cdot 5^{x + 1} = 40

Divide both sides by

4

5^{x + 1} = 10

Apply exponent rules

(x + 1) ln (5) = ln (10)

Solve

(x + 1) ln (5) = ln (10) : x = \frac{ln ( 10 )}{ln ( 5 )} - 1

x = \frac{ln ( 10 )}{ln ( 5 )} - 1

- e^{x} x = 0

n, (z^{2})^{n} = z^{10}

8^{x + 1} = 322

24 3^{x - 4} = 8 1^{x - 5}

What is the answer to 4\times 5^{x+1}-5=35 ?
The answer to 4\times 5^{x+1}-5=35 is x=(ln(10))/(ln(5))-1
Solve for x: 4\times 5^{x+1}-5=35
The solution is x=(ln(10))/(ln(5))-1