2^{2x}=2^6+8^2

Lösung

2^{2 x} = 2^{6} + 8^{2}

x = \frac{7}{2}

Dezimale

x = 3.5

Schritte zur Lösung

2^{2 x} = 2^{6} + 8^{2}

Wende Exponentenregel an

2 x = 7

Löse

2 x = 7 : x = \frac{7}{2}

x = \frac{7}{2}

e^{x + 1} = 5^{x + 5}

5^{4 x + 3} = 30

e^{- x} = 0.05

2^{5 x} = 6

e^{x} + x + 1 = 0