5^{1-2x}=3^{x+3}

Lösung

5^{1 - 2 x} = 3^{x + 3}

x = - \frac{3 ln ( 3 ) - ln ( 5 )}{ln ( 75 )}

Dezimale

x = - 0.39059 \dots

Schritte zur Lösung

5^{1 - 2 x} = 3^{x + 3}

Wende Exponentenregel an

(1 - 2 x) ln (5) = (x + 3) ln (3)

Löse

(1 - 2 x) ln (5) = (x + 3) ln (3) : x = - \frac{3 ln ( 3 ) - ln ( 5 )}{ln ( 75 )}

x = - \frac{3 ln ( 3 ) - ln ( 5 )}{ln ( 75 )}

e^{x^{2}} = e^{9}

a^{x + 1} - a^{x} = 1

4^{x} - 9 \times 2^{x} + 8 = 0

so l v e f or x, 5^{2 x - 3} = 3^{3 x + 4}

12 5^{2 x + 3} = 5^{x + 4}