3^x=2^{2-x}

Lösung

3^{x} = 2^{2 - x}

x = \frac{2 ln ( 2 )}{ln ( 6 )}

Dezimale

x = 0.77370 \dots

Schritte zur Lösung

3^{x} = 2^{2 - x}

Wende Exponentenregel an

x ln (3) = (2 - x) ln (2)

Löse

x ln (3) = (2 - x) ln (2) : x = \frac{2 ln ( 2 )}{ln ( 6 )}

x = \frac{2 ln ( 2 )}{ln ( 6 )}

2 e^{3 x} = 5 e^{8 x}

- 3 e^{- 3 t} = 1

3^{3 x - 1} = 6^{x - 5}

2^{2 x + 1} - 5 \cdot 2^{x} + 2 = 0

U (t) e^{t} - V (t) e^{- t} = 0