3^{x+5}=17^x

Lösung

3^{x + 5} = 1 7^{x}

x = \frac{5 ln ( 3 )}{ln ( 17 ) - ln ( 3 )}

Dezimale

x = 3.16675 \dots

Schritte zur Lösung

3^{x + 5} = 1 7^{x}

Wende Exponentenregel an

(x + 5) ln (3) = x ln (17)

Löse

(x + 5) ln (3) = x ln (17) : x = \frac{5 ln ( 3 )}{ln ( 17 ) - ln ( 3 )}

x = \frac{5 ln ( 3 )}{ln ( 17 ) - ln ( 3 )}

- e^{- x} + 6 e^{- 6 x} = 0

2^{3 x} = 1 6^{1 - x}

(5^{x})^{- 1} = 25

32 = 2^{x - 3}

1 0^{5 x} = 8