2^{2x-3}=5^{2-x}

Lösung

2^{2 x - 3} = 5^{2 - x}

x = \frac{ln ( 200 )}{ln ( 20 )}

Dezimale

x = 1.76862 \dots

Schritte zur Lösung

2^{2 x - 3} = 5^{2 - x}

Wende Exponentenregel an

(2 x - 3) ln (2) = (2 - x) ln (5)

Löse

(2 x - 3) ln (2) = (2 - x) ln (5) : x = \frac{ln ( 200 )}{ln ( 20 )}

x = \frac{ln ( 200 )}{ln ( 20 )}

0. 5^{x} = 0.15

5^{2 x - 1} = 0.2

100 = 75 e^{0.05 x}

1 4^{6 x} = 6 4^{x + 3}

5^{2 x - 1} + 2 = 7