2^{1-6x}=7^{3x+4}

Lösung

2^{1 - 6 x} = 7^{3 x + 4}

x = - \frac{4 ln ( 7 ) - ln ( 2 )}{3 ln ( 28 )}

Dezimale

x = - 0.70928 \dots

Schritte zur Lösung

2^{1 - 6 x} = 7^{3 x + 4}

Wende Exponentenregel an

(1 - 6 x) ln (2) = (3 x + 4) ln (7)

Löse

(1 - 6 x) ln (2) = (3 x + 4) ln (7) : x = - \frac{4 ln ( 7 ) - ln ( 2 )}{3 ln ( 28 )}

x = - \frac{4 ln ( 7 ) - ln ( 2 )}{3 ln ( 28 )}

e^{x} = 1 + x

8^{6 y + 4} = 64

3^{x} + 3^{x + 3} = 756

7 62 5^{x} = \frac{1}{12 5 ^{- x + 3}}

27 = 9^{x}