2^{5x-6}=16^{5x+3}

Lösung

2^{5 x - 6} = 1 6^{5 x + 3}

x = - \frac{6}{5}

Dezimale

x = - 1.2

Schritte zur Lösung

2^{5 x - 6} = 1 6^{5 x + 3}

Wende Exponentenregel an

5 x - 6 = 4 (5 x + 3)

Löse

5 x - 6 = 4 (5 x + 3) : x = - \frac{6}{5}

x = - \frac{6}{5}

e^{x^{x}} = 2

3^{x + 1} \cdot 2^{x + 1} = 36

7^{2 x} + 7^{x} - 42 = 0

3^{x} - 3^{- x} = \frac{728}{27}

7^{3 x + 4} = 4 9^{2 x + 1}