7^x=2^{2x+1}

Lösung

7^{x} = 2^{2 x + 1}

x = \frac{ln ( 2 )}{ln ( 7 ) - 2 ln ( 2 )}

Dezimale

x = 1.23861 \dots

Schritte zur Lösung

7^{x} = 2^{2 x + 1}

Wende Exponentenregel an

x ln (7) = (2 x + 1) ln (2)

Löse

x ln (7) = (2 x + 1) ln (2) : x = \frac{ln ( 2 )}{ln ( 7 ) - 2 ln ( 2 )}

x = \frac{ln ( 2 )}{ln ( 7 ) - 2 ln ( 2 )}

5^{r} + 1 = 51

85 \cdot 3^{x} = 765

2 9^{x} = 3 3^{x}

2 e^{2 x} - 3 e^{- 2 x} = 0

5^{2 x - 1} = 8^{x + 1}