4^{x+3}× 8^{2x-1}=sqrt(2)

Lösung

4^{x + 3} \cdot 8^{2 x - 1} = 2

x = - \frac{5}{16}

Dezimale

x = - 0.3125

Schritte zur Lösung

4^{x + 3} \cdot 8^{2 x - 1} = 2

Wende Exponentenregel an

2 x - 1 + 7 + 3 (2 x - 1) = \frac{1}{2}

Löse

2 x - 1 + 7 + 3 (2 x - 1) = \frac{1}{2} : x = - \frac{5}{16}

x = - \frac{5}{16}

5^{2 x + 1} + 3 \cdot 5^{6 x - 3} = 500

5 e^{- 0.13 t} = 1.7

8^{x - 3} = 16

e^{\frac{x}{5}} = 84

e^{x} = - 9 x