What is the answer to e^{x^2+4x}-15=3 ?

The answer to e^{x^2+4x}-15=3 is x=(-4+sqrt(16+4ln(18)))/2 ,x=(-4-sqrt(16+4ln(18)))/2

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e^{x^2+4x}-15=3

e^{x^{2} + 4 x} - 15 = 3

x = \frac{- 4 + 16 + 4 ln ( 18 )}{2}, x = \frac{- 4 - 16 + 4 ln ( 18 )}{2}

Decimal Notation

x = 0.62495 \dots, x = - 4.62495 \dots

Solution steps

e^{x^{2} + 4 x} - 15 = 3

Move

15

to the right side

e^{x^{2} + 4 x} = 18

Apply exponent rules

x^{2} + 4 x = ln (18)

Solve

x^{2} + 4 x = ln (18) : x = \frac{- 4 + 16 + 4 ln ( 18 )}{2}, x = \frac{- 4 - 16 + 4 ln ( 18 )}{2}

x = \frac{- 4 + 16 + 4 ln ( 18 )}{2}, x = \frac{- 4 - 16 + 4 ln ( 18 )}{2}

- 4 e^{- 4 x} = 0

- 4 e^{- 4 c} = \frac{e ^{- 12} - 1}{3}

9^{x} - 3^{x + 1} = 54

1 9^{x} = 2

5 \cdot 2^{x + 1} = 15

What is the answer to e^{x^2+4x}-15=3 ?
The answer to e^{x^2+4x}-15=3 is x=(-4+sqrt(16+4ln(18)))/2 ,x=(-4-sqrt(16+4ln(18)))/2