What are the solutions to the equation x^3+2x^2-40x+64=0 ?

The solutions to the equation x^3+2x^2-40x+64=0 are x=2,x=4,x=-8

Find the zeros of x^3+2x^2-40x+64=0

The zeros of x^3+2x^2-40x+64=0 are x=2,x=4,x=-8

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x^{3} + 2 x^{2} - 40 x + 64 = 0

x = 2, x = 4, x = - 8

Solution steps

x^{3} + 2 x^{2} - 40 x + 64 = 0

Factor

x^{3} + 2 x^{2} - 40 x + 64 : (x - 2) (x - 4) (x + 8)

(x - 2) (x - 4) (x + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x - 4 = 0 or x + 8 = 0

Solve

x - 2 = 0 : x = 2

Solve

x - 4 = 0 : x = 4

Solve

x + 8 = 0 : x = - 8

The solutions are

x = 2, x = 4, x = - 8

x^{3} + 3 x^{2} - 4 x - 12 = 0

z^{4} = - 83 + 8 i

2 = \frac{4}{3} π r^{3}

16 x^{4} = 1

1500 = 986 (1 + x)^{3}

What are the solutions to the equation x^3+2x^2-40x+64=0 ?
The solutions to the equation x^3+2x^2-40x+64=0 are x=2,x=4,x=-8
Find the zeros of x^3+2x^2-40x+64=0
The zeros of x^3+2x^2-40x+64=0 are x=2,x=4,x=-8