-x^3+0.8x^2+0.260625x-0.08775=0

Solución

- x^{3} + 0.8 x^{2} + 0.260625 x - 0.08775 = 0

x = \frac{9}{40}, x = - \frac{2}{5}, x = \frac{39}{40}

Notación decimal

x = 0.225, x = - 0.4, x = 0.975

Pasos de solución

- x^{3} + 0.8 x^{2} + 0.260625 x - 0.08775 = 0

Encontrar una solución para

- x^{3} + 0.8 x^{2} + 0.260625 x - 0.08775 = 0

utilizando el método de Newton-Raphson:

x \approx 0.22500 \dots

Aplicar la división larga

Eq u a t i o n 0 : \frac{- x ^{3} + 0.8 x ^{2} + 0.260625 x - 0.08775}{x - 0.225} = - x^{2} + 0.575 x + 0.39

- x^{2} + 0.575 x + 0.39 \approx 0

Encontrar una solución para

- x^{2} + 0.575 x + 0.39 = 0

utilizando el método de Newton-Raphson:

x \approx - 0.40000 \dots

Aplicar la división larga

Eq u a t i o n 0 : \frac{- x ^{2} + 0.575 x + 0.39}{x + 0.4} = - x + 0.975

- x + 0.975 \approx 0

x \approx 0.975

Aproximado a la forma algebraica

x = \frac{39}{40}

Aproximado a la forma algebraica

x \approx 0.22500 \dots : x = \frac{9}{40}

x \approx - 0.40000 \dots : x = - \frac{2}{5}

x = \frac{9}{40}, x = - \frac{2}{5}, x = \frac{39}{40}

Las soluciones son

x = \frac{9}{40}, x = - \frac{2}{5}, x = \frac{39}{40}

4 x^{3} - 120 x^{2} + 864 x - 1820 = 0

x^{3} + 5 x^{2} - 8 x - 12 = 0

x^{4} - 8 x^{2} + 16 = 0

x^{3} - 3 x^{2} + x - 3

2 m^{5} - 7 m^{4} + 12 m^{3} + 8 m^{2} = 0