y^2-6y+8=0

解

y^{2} - 6 y + 8 = 0

y = 4, y = 2

解答ステップ

y^{2} - 6 y + 8 = 0

解くとthe二次式

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 8 = 2

y_{1, 2} = \frac{- ( - 6 ) \pm 2}{2 \cdot 1}

解を分離する

y_{1} = \frac{- ( - 6 ) + 2}{2 \cdot 1}, y_{2} = \frac{- ( - 6 ) - 2}{2 \cdot 1}

y = \frac{- ( - 6 ) + 2}{2 \cdot 1} : 4

y = \frac{- ( - 6 ) - 2}{2 \cdot 1} : 2

二次equationの解:

y = 4, y = 2