1/(sqrt(1-x^2))= pi/3

Solución

\frac{1}{1 - x ^{2}} = \frac{π}{3}

x = \frac{- 9 + π ^{2}}{π}, x = - \frac{- 9 + π ^{2}}{π}

Notación decimal

x = 0.29683 \dots, x = - 0.29683 \dots

Pasos de solución

\frac{1}{1 - x ^{2}} = \frac{π}{3}

Utilizar multiplicación cruzada (regla de tres): Si

\frac{a}{b} = \frac{c}{d}

entonces

a \cdot d = b \cdot c

1 \cdot 3 = 1 - x^{2} π

Intercambiar lados

1 - x^{2} π = 1 \cdot 3

Multiplicar los numeros:

1 \cdot 3 = 3

1 - x^{2} π = 3

Dividir ambos lados entre

π

1 - x^{2} = \frac{3}{π}

Elevar al cuadrado ambos lados:

1 - x^{2} = \frac{9}{π ^{2}}

1 - x^{2} = \frac{9}{π ^{2}}

Resolver

1 - x^{2} = \frac{9}{π ^{2}} : x = \frac{- 9 + π ^{2}}{π}, x = - \frac{- 9 + π ^{2}}{π}

x = \frac{- 9 + π ^{2}}{π}, x = - \frac{- 9 + π ^{2}}{π}

Verificar las soluciones:

x = \frac{- 9 + π ^{2}}{π}

Verdadero

, x = - \frac{- 9 + π ^{2}}{π}

Verdadero

Las soluciones son

x = \frac{- 9 + π ^{2}}{π}, x = - \frac{- 9 + π ^{2}}{π}

g, v = 2 g h

x x - 8 = 3

18 x^{2} - 6 x + 1 = 3 x

14 x + 2 + 18 = 8