What is the answer to ln(4x-200)=5 ?

The answer to ln(4x-200)=5 is x=(e^5+200)/4

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ln(4x-200)=5

ln (4 x - 200) = 5

x = \frac{e ^{5} + 200}{4}

Decimal

x = 87.10328 \dots

Solution steps

ln (4 x - 200) = 5

Apply log rules

4 x - 200 = e^{5}

Solve

4 x - 200 = e^{5} : x = \frac{e ^{5} + 200}{4}

x = \frac{e ^{5} + 200}{4}

lo g_{2} (x^{2} - 3 x + 4) = 3

2 ln (x) - ln (7) = ln (112)

lo g_{3} (x^{2} - 8) = 0

4 x^{3} ln (x) + x^{3} = 0

2 ln (x) = 6

What is the answer to ln(4x-200)=5 ?
The answer to ln(4x-200)=5 is x=(e^5+200)/4
Solve for x: ln(4x-200)=5
The solution is x=(e^5+200)/4