What is the answer to ln(x^3)-ln(x^6)+ln(x^4)=2 ?

The answer to ln(x^3)-ln(x^6)+ln(x^4)=2 is x=e^2

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ln(x^3)-ln(x^6)+ln(x^4)=2

ln (x^{3}) - ln (x^{6}) + ln (x^{4}) = 2

x = e^{2}

Decimal

x = 7.38905 \dots

Solution steps

ln (x^{3}) - ln (x^{6}) + ln (x^{4}) = 2

Apply log rules

x = e^{2}

Verify Solutions:

x = e^{2}

True

The solution is

x = e^{2}

4 lo g_{2} (x - 1) = 0

lo g_{2} ((x + 4)^{3}) = 6

lo g_{10} (x^{2}) = - 0.407

15 = 19 ln (3 x + 3)

lo g_{x + 5} (2 x^{2} - 7 x + 7) = 2

What is the answer to ln(x^3)-ln(x^6)+ln(x^4)=2 ?
The answer to ln(x^3)-ln(x^6)+ln(x^4)=2 is x=e^2
Solve for x: ln(x^3)-ln(x^6)+ln(x^4)=2
The solution is x=e^2