log_{0.5}(12-8x)=-4

Lösung

lo g_{0.5} (12 - 8 x) = - 4

x = - \frac{1}{2}

Dezimale

x = - 0.5

Schritte zur Lösung

lo g_{0.5} (12 - 8 x) = - 4

Wende die log Regel an

12 - 8 x = 16

Löse

12 - 8 x = 16 : x = - \frac{1}{2}

x = - \frac{1}{2}

lo g_{10} (x) 0.004 = 2

ln (x + 8) = 2

lo g_{10} (2 x - 6) = 2

lo g_{256} (x) = - \frac{3}{4}

x (2 ln (x) + 1) = 0