What is the answer to log_{10}(x)=log_{10}(6)-log_{10}(5)+1 ?

The answer to log_{10}(x)=log_{10}(6)-log_{10}(5)+1 is x=12

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log_{10}(x)=log_{10}(6)-log_{10}(5)+1

lo g_{10} (x) = lo g_{10} (6) - lo g_{10} (5) + 1

x = 12

Solution steps

lo g_{10} (x) = lo g_{10} (6) - lo g_{10} (5) + 1

Apply log rules

x = 12

lo g_{2} (x) - lo g_{2} (x - 1) = 2

ln (x) - 6 x^{2} ln (x) = - 5 x ln (x)

x, y^{2} + ln (x y) = 2

3 lo g_{2} (x) = 5

ln (x^{8}) - 9 ln (x) = 6

What is the answer to log_{10}(x)=log_{10}(6)-log_{10}(5)+1 ?
The answer to log_{10}(x)=log_{10}(6)-log_{10}(5)+1 is x=12
Solve for x: log_{10}(x)=log_{10}(6)-log_{10}(5)+1
The solution is x=12