What is the answer to |x+1|=x^2-29 ?

The answer to |x+1|=x^2-29 is x=(-1-sqrt(113))/2 \lor x=6

Solve for x: |x+1|=x^2-29

The solution is x=(-1-sqrt(113))/2 \lor x=6

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∣ x + 1 ∣ = x^{2} - 29

x = \frac{- 1 - 113}{2} or x = 6

Decimal

x = - 5.81507 \dots, x = 6

Solution steps

∣ x + 1 ∣ = x^{2} - 29

Find positive and negative intervals

x < - 1, x \geq - 1

Solve the inequality for each interval

x = \frac{- 1 - 113}{2} or x = 6

∣ x + 3 ∣ - 6 = 3

\frac{∣ a + 5 ∣ - 5}{- 2} = 2

∣ 2 y - 3 ∣ = ∣ 3 - 2 y ∣

2 x + ∣ x + 1 ∣ = 2

∣ 5 x - 1 ∣ = 4 x + 2

What is the answer to |x+1|=x^2-29 ?
The answer to |x+1|=x^2-29 is x=(-1-sqrt(113))/2 \lor x=6
Solve for x: |x+1|=x^2-29
The solution is x=(-1-sqrt(113))/2 \lor x=6