What is the answer to |x^2-2x-5|=3 ?

The answer to |x^2-2x-5|=3 is x=-2\lor x=1-sqrt(3)\lor x=1+sqrt(3)\lor x=4

Solve for x: |x^2-2x-5|=3

The solution is x=-2\lor x=1-sqrt(3)\lor x=1+sqrt(3)\lor x=4

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x^{2} - 2 x - 5 = 3

x = - 2 or x = 1 - 3 or x = 1 + 3 or x = 4

Decimal

x = - 2, x = - 0.73205 \dots, x = 2.73205 \dots, x = 4

Solution steps

x^{2} - 2 x - 5 = 3

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 2 x - 5 = - 3 or x^{2} - 2 x - 5 = 3

x^{2} - 2 x - 5 = - 3 or x^{2} - 2 x - 5 = 3

(x = 1 - 3 or x = 1 + 3) or (x = - 2 or x = 4)

x = - 2 or x = 1 - 3 or x = 1 + 3 or x = 4

\frac{4 x - 8}{2} = 8

∣ x - 1 ∣ + 2 = ∣ x + 1 ∣

∣ 3 s - 4 ∣ = ∣ s + 1 ∣

∣ x + 2 ∣ + ∣ x - 3 ∣ = 7

∣ 4 x + 6 ∣ = 7

What is the answer to |x^2-2x-5|=3 ?
The answer to |x^2-2x-5|=3 is x=-2\lor x=1-sqrt(3)\lor x=1+sqrt(3)\lor x=4
Solve for x: |x^2-2x-5|=3
The solution is x=-2\lor x=1-sqrt(3)\lor x=1+sqrt(3)\lor x=4