|x-2||x+4|=3

解

∣ x - 2 ∣ ∣ x + 4 ∣ = 3

x = - 1 - 23 or x = - 1 - 6 or x = 6 - 1 or x = - 1 + 23

十進法表記

x = - 4.46410 \dots, x = - 3.44948 \dots, x = 1.44948 \dots, x = 2.46410 \dots

解答ステップ

∣ x - 2 ∣ ∣ x + 4 ∣ = 3

正と負の区間を求める

x < - 4, - 4 \leq x < 2, x \geq 2

各区間の不等式を解く

x = - 1 - 23 or (x = - 1 - 6 or x = 6 - 1) or x = - 1 + 23

x = - 1 - 23 or x = - 1 - 6 or x = 6 - 1 or x = - 1 + 23