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受欢迎的代数 >

-30c^1e^{(-30)}=-10^6*(c^1+c^2-1)

解答

- 30 \cdot c^{1} \cdot e^{(- 30)} = - 1 0^{6} \cdot (c^{1} + c^{2} - 1)

解答

c = - \frac{1000000 + 100000 0 ^{2} + 4000000000000}{2000000}, c = \frac{100000 0 ^{2} + 4000000000000 - 1000000}{2000000}

+1

十进制

c = - 1.61803 \dots, c = 0.61803 \dots

求解步骤

- 30 c^{1} e^{(- 30)} = - 1 0^{6} (c^{1} + c^{2} - 1)

展开

- 30 c^{1} e^{- 30} : - \frac{30}{e ^{30}} c

展开

- 1 0^{6} (c^{1} + c^{2} - 1) : - 1000000 c - 1000000 c^{2} + 1000000

- \frac{30}{e ^{30}} c = - 1000000 c - 1000000 c^{2} + 1000000

交换两边

- 1000000 c - 1000000 c^{2} + 1000000 = - \frac{30}{e ^{30}} c

将

\frac{30}{e ^{30}} c

para o lado esquerdo

- 1000000 c^{2} - 1000000 c + 1000000 = 0

使用求根公式求解

c_{1, 2} = \frac{- ( - 1000000 ) \pm ( - 1000000 ) ^{2} - 4 ( - 1000000 ) \cdot 1000000}{2 ( - 1000000 )}

(- 1000000)^{2} - 4 (- 1000000) \cdot 1000000 = 100000 0^{2} + 4000000000000

c_{1, 2} = \frac{- ( - 1000000 ) \pm 100000 0 ^{2} + 4000000000000}{2 ( - 1000000 )}

将解分隔开

c_{1} = \frac{- ( - 1000000 ) + 100000 0 ^{2} + 4000000000000}{2 ( - 1000000 )}, c_{2} = \frac{- ( - 1000000 ) - 100000 0 ^{2} + 4000000000000}{2 ( - 1000000 )}

c = \frac{- ( - 1000000 ) + 100000 0 ^{2} + 4000000000000}{2 ( - 1000000 )} : - \frac{1000000 + 100000 0 ^{2} + 4000000000000}{2000000}

c = \frac{- ( - 1000000 ) - 100000 0 ^{2} + 4000000000000}{2 ( - 1000000 )} : \frac{100000 0 ^{2} + 4000000000000 - 1000000}{2000000}

二次方程组的解是:

c = - \frac{1000000 + 100000 0 ^{2} + 4000000000000}{2000000}, c = \frac{100000 0 ^{2} + 4000000000000 - 1000000}{2000000}

作图

流行的例子

∣ 2 x - 1 ∣ > 3

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f a c t or 4 x^{3} - 28 x^{2} + 40 x

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因式分解 4x(2x-1)+(2x-1)^2

f a c t or 4 x (2 x - 1) + (2 x - 1)^{2}