de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Algebra >

faktorisieren (x^2-6x)^2+13(x^2-6x)+40

Lösung

faktorisieren

(x^{2} - 6 x)^{2} + 13 (x^{2} - 6 x) + 40

Lösung

(x - 1) (x - 5) (x - 2) (x - 4)

Schritte zur Lösung

(x^{2} - 6 x)^{2} + 13 (x^{2} - 6 x) + 40

Zerlege die Ausdrücke in Gruppen

= ((x^{2} - 6 x)^{2} + 5 (x^{2} - 6 x)) + (8 (x^{2} - 6 x) + 40)

Klammere

(x^{2} - 6 x)

aus

(x^{2} - 6 x)^{2} + 5 (x^{2} - 6 x)

aus

: (x^{2} - 6 x) ((x^{2} - 6 x) + 5)

Klammere

8

aus

8 (x^{2} - 6 x) + 40

aus

: 8 ((x^{2} - 6 x) + 5)

= (x^{2} - 6 x) ((x^{2} - 6 x) + 5) + 8 ((x^{2} - 6 x) + 5)

Klammere gleiche Terme aus

(x^{2} - 6 x) + 5

= ((x^{2} - 6 x) + 5) ((x^{2} - 6 x) + 8)

Fasse zusammen

= (x^{2} - 6 x + 5) (x^{2} - 6 x + 8)

Faktorisiere

(x^{2} - 6 x + 5) (x^{2} - 6 x + 8) : (x - 1) (x - 5) (x - 2) (x - 4)

= (x^{2} - 6 x + 5) (x^{2} - 6 x + 8)

Faktorisiere

x^{2} - 6 x + 5 : (x - 1) (x - 5)

= (x - 1) (x - 5) (x^{2} - 6 x + 8)

Faktorisiere

x^{2} - 6 x + 8 : (x - 2) (x - 4)

= (x - 1) (x - 5) (x - 2) (x - 4)

Beliebte Beispiele

\frac{x}{5} \leq - \frac{3}{5}

7 - (5 t - 13) = - 25

(120(1)^2)/((1)^2+4)

\frac{120 ( 1 ) ^{2}}{( 1 ) ^{2} + 4}

(0.25)/(36)= r/(60)

\frac{0.25}{36} = \frac{r}{60}

2 > - 3 t - 10