|x^2+5x+3|=3

Lösung

x^{2} + 5 x + 3 = 3

x = - 5 or x = - 3 or x = - 2 or x = 0

Schritte zur Lösung

x^{2} + 5 x + 3 = 3

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

x^{2} + 5 x + 3 = - 3 or x^{2} + 5 x + 3 = 3

x^{2} + 5 x + 3 = - 3 or x^{2} + 5 x + 3 = 3

(x = - 3 or x = - 2) or (x = - 5 or x = 0)

x = - 5 or x = - 3 or x = - 2 or x = 0

∣ 5 x + 3 ∣ + 4 = 11

9 x = 63

(x - 4)^{2} \geq 9

x^{2} + 5 x > 0

∣ b ∣ = 3