u^2-10u+24=0

解

u^{2} - 10 u + 24 = 0

u = 6, u = 4

解答ステップ

u^{2} - 10 u + 24 = 0

解くとthe二次式

u_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 24 = 2

u_{1, 2} = \frac{- ( - 10 ) \pm 2}{2 \cdot 1}

解を分離する

u_{1} = \frac{- ( - 10 ) + 2}{2 \cdot 1}, u_{2} = \frac{- ( - 10 ) - 2}{2 \cdot 1}

u = \frac{- ( - 10 ) + 2}{2 \cdot 1} : 6

u = \frac{- ( - 10 ) - 2}{2 \cdot 1} : 4

二次equationの解:

u = 6, u = 4