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Popular >

|x+3|+2>= 6

Solution

∣ x + 3 ∣ + 2 \geq 6

Solution

x \leq - 7 or x \geq 1

+1

Interval Notation

(- \infty, - 7] \cup [1, \infty)

Solution steps

∣ x + 3 ∣ + 2 \geq 6

Move

2

to the right side

∣ x + 3 ∣ \geq 4

Apply absolute rule: If

∣ u ∣ \geq a, a > 0

then

u \leq - a

or

u \geq a

x + 3 \leq - 4 or x + 3 \geq 4

x + 3 \leq - 4 or x + 3 \geq 4

x \leq - 7 or x \geq 1

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\frac{50 !}{2 ! ( 48 ! )}

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\frac{1}{6} \times \frac{5}{6} + \frac{5}{6} \times \frac{1}{6}

Frequently Asked Questions (FAQ)

What is |x+3|+2>= 6 ?
The solution to |x+3|+2>= 6 is x<=-7\lor x>= 1