What are the solutions to the equation 4x^2+4x+1=0 ?

The solutions to the equation 4x^2+4x+1=0 are x=-1/2

Find the zeros of 4x^2+4x+1=0

The zeros of 4x^2+4x+1=0 are x=-1/2

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4 x^{2} + 4 x + 1 = 0

x = - \frac{1}{2}

Decimal Notation

x = - 0.5

Solution steps

4 x^{2} + 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

4^{2} - 4 \cdot 4 \cdot 1 = 0

x_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 4}

x = \frac{- 4}{2 \cdot 4}

\frac{- 4}{2 \cdot 4} = - \frac{1}{2}

x = - \frac{1}{2}

The solution to the quadratic equation is:

x = - \frac{1}{2}

32 + 4 x = - 13

\frac{c}{0.3} = - 2.7

2 x + 3 = - 2 x + 15

8 x + 3 = 8 x + 27

3 (- 2)^{3}

What are the solutions to the equation 4x^2+4x+1=0 ?
The solutions to the equation 4x^2+4x+1=0 are x=-1/2
Find the zeros of 4x^2+4x+1=0
The zeros of 4x^2+4x+1=0 are x=-1/2