vereinfachen (2-i)/(3-i)-1/5 [(1+8i)/(1+3i)]

Lösung

vereinfachen

\frac{2 - i}{3 - i} - \frac{1}{5} [\frac{1 + 8 i}{1 + 3 i}]

\frac{1}{5} - \frac{1}{5} i

Schritte zur Lösung

\frac{2 - i}{3 - i} - \frac{1}{5} (\frac{1 + 8 i}{1 + 3 i})

\frac{2 - i}{3 - i} = \frac{7 - i}{10}

\frac{1 + 8 i}{1 + 3 i} = \frac{25 + 5 i}{10}

= \frac{7 - i}{10} - \frac{1}{5} \cdot \frac{25 + 5 i}{10}

Vereinfache

\frac{1}{5} \cdot \frac{25 + 5 i}{10} : \frac{\frac{5}{2} + \frac{1}{2} i}{5}

= \frac{7 - i}{10} - \frac{\frac{5}{2} + \frac{1}{2} i}{5}

Füge zusammen:

\frac{7 - i}{10} - \frac{\frac{5}{2} + \frac{1}{2} i}{5} : \frac{- i + 1}{5}

= \frac{- i + 1}{5}

Rewrite in standard complex form:

\frac{1}{5} - \frac{1}{5} i

= \frac{1}{5} - \frac{1}{5} i

6 x^{2} + 24 x - 1710 = 0

- x^{2} + 3 x + 10 = 0

∣ y + 1 ∣ < \frac{2}{∣ y ∣}

s im pl i f y 10000 0^{\frac{3}{5}}

\frac{3}{4} + (\frac{1}{3} \div \frac{1}{6}) - (- \frac{1}{2})