What are the solutions to the equation 0=5x^2-5x-24 ?

The solutions to the equation 0=5x^2-5x-24 are x=(5+sqrt(505))/(10),x=(5-sqrt(505))/(10)

Find the zeros of 0=5x^2-5x-24

The zeros of 0=5x^2-5x-24 are x=(5+sqrt(505))/(10),x=(5-sqrt(505))/(10)

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0 = 5 x^{2} - 5 x - 24

x = \frac{5 + 505}{10}, x = \frac{5 - 505}{10}

Decimal Notation

x = 2.74722 \dots, x = - 1.74722 \dots

Solution steps

0 = 5 x^{2} - 5 x - 24

Switch sides

5 x^{2} - 5 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 5 ( - 24 )}{2 \cdot 5}

(- 5)^{2} - 4 \cdot 5 (- 24) = 505

x_{1, 2} = \frac{- ( - 5 ) \pm 505}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 505}{2 \cdot 5}, x_{2} = \frac{- ( - 5 ) - 505}{2 \cdot 5}

x = \frac{- ( - 5 ) + 505}{2 \cdot 5} : \frac{5 + 505}{10}

x = \frac{- ( - 5 ) - 505}{2 \cdot 5} : \frac{5 - 505}{10}

The solutions to the quadratic equation are:

x = \frac{5 + 505}{10}, x = \frac{5 - 505}{10}

i^{80}

46 x - 23 = 46 x + 23

x^{2} - 0.8 x - 0.4 = 5 x^{2} - 4 x - 2

\frac{12 !}{6 ! 6 !}

2 x^{2} + 3 x + 4 = 0

What are the solutions to the equation 0=5x^2-5x-24 ?
The solutions to the equation 0=5x^2-5x-24 are x=(5+sqrt(505))/(10),x=(5-sqrt(505))/(10)
Find the zeros of 0=5x^2-5x-24
The zeros of 0=5x^2-5x-24 are x=(5+sqrt(505))/(10),x=(5-sqrt(505))/(10)