|((X+1))/(X-2)|>2

Lösung

\frac{( X + 1 )}{X - 2} > 2

1 < X < 2 or 2 < X < 5

Intervall-Notation

(1, 2) \cup (2, 5)

Schritte zur Lösung

\frac{X + 1}{X - 2} > 2

Wende Absoluteregel an: Wenn

∣ u ∣ > a, a > 0

dann

u < - a

u > a

\frac{X + 1}{X - 2} < - 2 or \frac{X + 1}{X - 2} > 2

\frac{X + 1}{X - 2} < - 2 or \frac{X + 1}{X - 2} > 2

1 < X < 2 or 2 < X < 5

s im pl i f y \frac{3}{2 - 5 i}

∣ 7 a + 2 ∣ - 8 = 8

57 = \frac{1}{2} D + 12

3 x^{2} - 42 x + 147 = 0

x + 1 > 0