What are the solutions to the equation x^2-4x-140=0 ?

The solutions to the equation x^2-4x-140=0 are x=14,x=-10

Find the zeros of x^2-4x-140=0

The zeros of x^2-4x-140=0 are x=14,x=-10

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x^{2} - 4 x - 140 = 0

x = 14, x = - 10

Solution steps

x^{2} - 4 x - 140 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 140 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 140) = 24

x_{1, 2} = \frac{- ( - 4 ) \pm 24}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 24}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 24}{2 \cdot 1}

x = \frac{- ( - 4 ) + 24}{2 \cdot 1} : 14

x = \frac{- ( - 4 ) - 24}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 14, x = - 10

- 9 x^{2} - 3 x + 2

6 (x - 7) - 7 (x - 6) = x + 6 - (x - 5)

x - 2 = - \frac{1}{6} x + \frac{1}{3}

4 x + 5 = 89 + 8

31 = 5 (b - 2)

What are the solutions to the equation x^2-4x-140=0 ?
The solutions to the equation x^2-4x-140=0 are x=14,x=-10
Find the zeros of x^2-4x-140=0
The zeros of x^2-4x-140=0 are x=14,x=-10