因式分解 2^{n+1}+3(2^n)+2^{n-1}

解答

因式分解

2^{n + 1} + 3 (2^{n}) + 2^{n - 1}

11 \cdot 2^{n - 1}

求解步骤

2^{n + 1} + 3 (2^{n}) + 2^{n - 1}

使用法则:

(a) = a

(2^{n}) = 2^{n}

= 2^{n + 1} + 3 \cdot 2^{n} + 2^{n - 1}

因式分解出通项

2^{n - 1} : 2^{n - 1} (2^{2} + 3 \cdot 2 + 1)

= 2^{n - 1} (2^{2} + 3 \cdot 2 + 1)

2^{2} + 3 \cdot 2 + 1 = 11

= 2^{n - 1} \cdot 11

= 11 \cdot 2^{n - 1}

a - (- 3.75) = 6.11

f a c t or 2 y^{2} - 11 y + 12

s im pl i f y \frac{8 ^{2}}{a ^{2}}

5 x - 3 = 17

3^{x - 2} = 18