What are the solutions to the equation 9x^2+6x=3 ?

The solutions to the equation 9x^2+6x=3 are x= 1/3 ,x=-1

Find the zeros of 9x^2+6x=3

The zeros of 9x^2+6x=3 are x= 1/3 ,x=-1

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9 x^{2} + 6 x = 3

x = \frac{1}{3}, x = - 1

Decimal Notation

x = 0.33333 \dots, x = - 1

Solution steps

9 x^{2} + 6 x = 3

Move

3

to the left side

9 x^{2} + 6 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 ( - 3 )}{2 \cdot 9}

6^{2} - 4 \cdot 9 (- 3) = 12

x_{1, 2} = \frac{- 6 \pm 12}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 6 + 12}{2 \cdot 9}, x_{2} = \frac{- 6 - 12}{2 \cdot 9}

x = \frac{- 6 + 12}{2 \cdot 9} : \frac{1}{3}

x = \frac{- 6 - 12}{2 \cdot 9} : - 1

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 1

x^{2} + 2 x + 1 > 9

50 \cdot 9.8

\frac{1}{2} a + \frac{3}{2} b

∣ x + 5 ∣ \geq 7

2 x^{2} + 4 x - 1 = 0

What are the solutions to the equation 9x^2+6x=3 ?
The solutions to the equation 9x^2+6x=3 are x= 1/3 ,x=-1
Find the zeros of 9x^2+6x=3
The zeros of 9x^2+6x=3 are x= 1/3 ,x=-1