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Beliebt Algebra >

faktorisieren 2m^pn^r+6m^{p-1}n^{r+1}-12m^{p+1}n^{r-1}

Lösung

faktorisieren

2 m^{p} n^{r} + 6 m^{p - 1} n^{r + 1} - 12 m^{p + 1} n^{r - 1}

Lösung

2 m^{p - 1} n^{r - 1} (3 n^{2} - 6 m^{2} + nm)

Schritte zur Lösung

2 m^{p} n^{r} + 6 m^{p - 1} n^{r + 1} - 12 m^{p + 1} n^{r - 1}

Klammere gleiche Terme aus

2 m^{p - 1} n^{r - 1} : 2 m^{p - 1} n^{r - 1} (mn + 3 n^{2} - 6 m^{2})

= 2 m^{p - 1} n^{r - 1} (mn + 3 n^{2} - 6 m^{2})

= 2 m^{p - 1} n^{r - 1} (3 n^{2} - 6 m^{2} + nm)

Beliebte Beispiele

21 < 3 (5 - 2 x) < 39

- 2 < x < 5

x + 7 = 15

5 x + x^{2} + 9 = 0

faktorisieren 2x^2-98

f a c t or 2 x^{2} - 98