|2x-3|>= 2

Lösung

∣ 2 x - 3 ∣ \geq 2

x \leq \frac{1}{2} or x \geq \frac{5}{2}

Intervall-Notation

(- \infty, \frac{1}{2}] \cup [\frac{5}{2}, \infty)

Dezimale

x \leq 0.5 or x \geq 2.5

Schritte zur Lösung

∣ 2 x - 3 ∣ \geq 2

Wende Absoluteregel an: Wenn

∣ u ∣ \geq a, a > 0

dann

u \leq - a

u \geq a

2 x - 3 \leq - 2 or 2 x - 3 \geq 2

2 x - 3 \leq - 2 or 2 x - 3 \geq 2

x \leq \frac{1}{2} or x \geq \frac{5}{2}

∣ 1 - x ∣ = x - 1

4 (u - 1) - 1 = 2 (2 u - 3)

- 90 > - 5 (k - 3)

4 (x + 2) < - 2 (x - 1)

- (3 x + 4) - (- 5 x - 3) = 0