What are the solutions to the equation x(2x+4)=240 ?

The solutions to the equation x(2x+4)=240 are x=10,x=-12

Find the zeros of x(2x+4)=240

The zeros of x(2x+4)=240 are x=10,x=-12

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x (2 x + 4) = 240

x = 10, x = - 12

Solution steps

x (2 x + 4) = 240

Expand

x (2 x + 4) : 2 x^{2} + 4 x

2 x^{2} + 4 x = 240

Move

240

to the left side

2 x^{2} + 4 x - 240 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 ( - 240 )}{2 \cdot 2}

4^{2} - 4 \cdot 2 (- 240) = 44

x_{1, 2} = \frac{- 4 \pm 44}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 4 + 44}{2 \cdot 2}, x_{2} = \frac{- 4 - 44}{2 \cdot 2}

x = \frac{- 4 + 44}{2 \cdot 2} : 10

x = \frac{- 4 - 44}{2 \cdot 2} : - 12

The solutions to the quadratic equation are:

x = 10, x = - 12

10 u + 7 = 8 (2 u - 4) - 9

\frac{9}{5} c + 32

\frac{2}{4} = \frac{4}{2}

3 x + 4 < - 5

5 (x - 1)^{2} = 50

What are the solutions to the equation x(2x+4)=240 ?
The solutions to the equation x(2x+4)=240 are x=10,x=-12
Find the zeros of x(2x+4)=240
The zeros of x(2x+4)=240 are x=10,x=-12