化简 log_{49}(7)+log_{243}(27)-log_{25}(125)

解答

化简

lo g_{49} (7) + lo g_{243} (27) - lo g_{25} (125)

- \frac{2}{5}

十进制

- 0.4

求解步骤

lo g_{49} (7) + lo g_{243} (27) - lo g_{25} (125)

lo g_{49} (7) = \frac{1}{2}

lo g_{243} (27) = \frac{3}{5}

lo g_{25} (125) = \frac{3}{2}

= \frac{1}{2} + \frac{3}{5} - \frac{3}{2}

\frac{1}{2} + \frac{3}{5} - \frac{3}{2} = - \frac{2}{5}

= - \frac{2}{5}

2 x^{3} - 8 x^{2} > 0

f a c t or 18 n^{4} - 30 n^{2} p + 50 p^{2}

f a c t or 3 n^{2} - 6 n + 3

5 x + 15 (6) = 30

f a c t or 4 x^{2} - 11 x - 45