(x-1)(x+4)(4-x)<0

Lösung

(x - 1) (x + 4) (4 - x) < 0

- 4 < x < 1 or x > 4

Intervall-Notation

(- 4, 1) \cup (4, \infty)

Schritte zur Lösung

(x - 1) (x + 4) (4 - x) < 0

Identifiziere die Intervalle

- 4 < x < 1 or x > 4

7 x^{2} = 112

f a c t or x^{2} + 3 x y - 18 y^{2}

15 < - \frac{2}{3} (x - 18)

2 (x + 3) \leq 3 - x

y^{2} + 8 y = 10