9x^2+24x+32=0

解答

9 x^{2} + 24 x + 32 = 0

x = - \frac{4}{3} + i \frac{4}{3}, x = - \frac{4}{3} - i \frac{4}{3}

求解步骤

9 x^{2} + 24 x + 32 = 0

使用求根公式求解

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 9 \cdot 32}{2 \cdot 9}

化简

2 4^{2} - 4 \cdot 9 \cdot 32 : 24 i

x_{1, 2} = \frac{- 24 \pm 24 i}{2 \cdot 9}

将解分隔开

x_{1} = \frac{- 24 + 24 i}{2 \cdot 9}, x_{2} = \frac{- 24 - 24 i}{2 \cdot 9}

x = \frac{- 24 + 24 i}{2 \cdot 9} : - \frac{4}{3} + i \frac{4}{3}

x = \frac{- 24 - 24 i}{2 \cdot 9} : - \frac{4}{3} - i \frac{4}{3}

二次方程组的解是:

x = - \frac{4}{3} + i \frac{4}{3}, x = - \frac{4}{3} - i \frac{4}{3}

f a c t or 4 x^{2} - 36 x y + 81 y^{2}

s im pl i f y \frac{15 x ^{6} y}{25 x ^{2} y ^{4}}

s im pl i f y \frac{4 j ^{7}}{5 ( j ^{2} ) ^{3}}

x^{2} \leq 3 - 2 x

f a c t or x^{3} y^{3} + 2 x^{3} + 5 x^{2} y^{3} + 10 x^{2}