zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的代数 >

因式分解 9(p-q)^2+12(p^2-q^2)+4(p+q)^2

解答

因式分解

9 (p - q)^{2} + 12 (p^{2} - q^{2}) + 4 (p + q)^{2}

解答

(5 p - q)^{2}

求解步骤

9 (p - q)^{2} + 12 (p^{2} - q^{2}) + 4 (p + q)^{2}

12 (p^{2} - q^{2}) = 12 (p + q) (p - q)

= 9 (p - q)^{2} + 12 (p + q) (p - q) + 4 (p + q)^{2}

(p - q)^{2} : p^{2} - 2 pq + q^{2}

= 9 (p^{2} - 2 pq + q^{2}) + 12 (p + q) (p - q) + 4 (p + q)^{2}

(p + q)^{2} : p^{2} + 2 pq + q^{2}

= 9 (p^{2} - 2 pq + q^{2}) + 12 (p + q) (p - q) + 4 (p^{2} + 2 pq + q^{2})

乘开

9 (p^{2} - 2 pq + q^{2}) : 9 p^{2} - 18 pq + 9 q^{2}

= 9 p^{2} - 18 pq + 9 q^{2} + 12 (p + q) (p - q) + 4 (p^{2} + 2 pq + q^{2})

乘开

12 (p + q) (p - q) : 12 p^{2} - 12 q^{2}

= 9 p^{2} - 18 pq + 9 q^{2} + 12 p^{2} - 12 q^{2} + 4 (p^{2} + 2 pq + q^{2})

乘开

4 (p^{2} + 2 pq + q^{2}) : 4 p^{2} + 8 pq + 4 q^{2}

= 9 p^{2} - 18 pq + 9 q^{2} + 12 p^{2} - 12 q^{2} + 4 p^{2} + 8 pq + 4 q^{2}

化简

9 p^{2} - 18 pq + 9 q^{2} + 12 p^{2} - 12 q^{2} + 4 p^{2} + 8 pq + 4 q^{2} : 25 p^{2} - 10 pq + q^{2}

= 25 p^{2} - 10 pq + q^{2}

将

25 p^{2} - 10 pq + q^{2}

改写为

(5 p)^{2} - 2 \cdot 5 pq + q^{2}

= (5 p)^{2} - 2 \cdot 5 pq + q^{2}

使用完全平方公式:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

a = 5 p, b = q

= (5 p - q)^{2}

流行的例子

2 x + 8 = - 10

化简 2sqrt(x)*2sqrt(x)

s im pl i f y 2 x \cdot 2 x

\frac{3}{2} + 3 - 8

\frac{x}{2} + \frac{x}{6} = 1

16 = \frac{4}{3} (8 x + 3)