(x+2)/(x+3)<0

Lösung

\frac{x + 2}{x + 3} < 0

- 3 < x < - 2

Intervall-Notation

(- 3, - 2)

Schritte zur Lösung

\frac{x + 2}{x + 3} < 0

Identifiziere die Intervalle

- 3 < x < - 2

f a c t or a^{2} - b^{2} + 4 a - 4 b

r > 15 - 2 r

f a c t or 2 x^{2} - 17 x + 8

9 y^{2} + 5 = - 76

6 - 4 x = 6