6v^2+12v=0

解

6 v^{2} + 12 v = 0

v = 0, v = - 2

解答ステップ

6 v^{2} + 12 v = 0

解くとthe二次式

v_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 6 \cdot 0}{2 \cdot 6}

1 2^{2} - 4 \cdot 6 \cdot 0 = 12

v_{1, 2} = \frac{- 12 \pm 12}{2 \cdot 6}

解を分離する

v_{1} = \frac{- 12 + 12}{2 \cdot 6}, v_{2} = \frac{- 12 - 12}{2 \cdot 6}

v = \frac{- 12 + 12}{2 \cdot 6} : 0

v = \frac{- 12 - 12}{2 \cdot 6} : - 2

二次equationの解:

v = 0, v = - 2