What is the answer to |p-3|=10 ?

The answer to |p-3|=10 is p=-7\lor p=13

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|p-3|=10

∣ p - 3 ∣ = 10

p = - 7 or p = 13

Solution steps

∣ p - 3 ∣ = 10

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

p - 3 = - 10 or p - 3 = 10

p - 3 = - 10 or p - 3 = 10

p = - 7 or p = 13

3 x^{2} - 4 x - 15

x^{3} - 2 x + 1

4 x^{(3)} + 8 x^{(2)} - x - 2

4 (a + b)^{2} + 11 (a + b) - 3

- \frac{\frac{16}{49}}{( - \frac{4}{35} )}