|x|<= 13

Lösung

∣ x ∣ \leq 13

- 13 \leq x \leq 13

Intervall-Notation

[- 13, 13]

Schritte zur Lösung

∣ x ∣ \leq 13

Wende Absoluteregel an: Wenn

∣ u ∣ \leq a, a > 0

dann

- a \leq u \leq a

- 13 \leq x \leq 13

4 (2 x + 8) = 5

3 (x - 1) \leq 6 x - 1

\frac{x - 2}{x + 4} \leq 0

8 y + 11 = 2 y + 29

1 0^{2} + 1 2^{2}