What is (2t^{-3})^3(0.4r)^2 ?

The solution to (2t^{-3})^3(0.4r)^2 is (1.28r^2)/(t^9)

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simplify (2t^{-3})^3(0.4r)^2

simplify

(2 t^{- 3})^{3} (0.4 r)^{2}

\frac{1.28 r ^{2}}{t ^{9}}

Solution steps

(2 t^{- 3})^{3} (0.4 r)^{2}

Simplify

(2 t^{- 3})^{3} : \frac{8}{t ^{9}}

= \frac{8}{t ^{9}} (0.4 r)^{2}

Simplify

(0.4 r)^{2} : 0.16 r^{2}

= \frac{8}{t ^{9}} \cdot 0.16 r^{2}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{8 \cdot 0.16 r ^{2}}{t ^{9}}

Multiply the numbers:

8 \cdot 0.16 = 1.28

= \frac{1.28 r ^{2}}{t ^{9}}

\frac{x ^{2} - 9}{x - 1} \leq 0

2 w^{2} - 3 w - 3 = 0

\frac{1}{15} + \frac{1}{3}

\frac{1}{2} \cdot \frac{6}{5}

25 - x^{2} \cdot x + 3

What is (2t^{-3})^3(0.4r)^2 ?
The solution to (2t^{-3})^3(0.4r)^2 is (1.28r^2)/(t^9)