What are the solutions to the equation (9-λ)*(4-λ)=0 ?

The solutions to the equation (9-λ)*(4-λ)=0 are λ=9,λ=4

Find the zeros of (9-λ)*(4-λ)=0

The zeros of (9-λ)*(4-λ)=0 are λ=9,λ=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(9 - λ) \cdot (4 - λ) = 0

λ = 9, λ = 4

Solution steps

(9 - λ) (4 - λ) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

9 - λ = 0 or 4 - λ = 0

Solve

9 - λ = 0 : λ = 9

Solve

4 - λ = 0 : λ = 4

The solutions to the quadratic equation are:

λ = 9, λ = 4

(∣ x + 4 ∣^{2} - 25) \cdot (x^{2} - 9) \leq 0

5 (5 x + 7) = 3 (3 x + 4) + 55

8 = x 3

(2 x^{3} y^{- 3})^{- 2}

9 - 6 x + x^{2}

What are the solutions to the equation (9-λ)*(4-λ)=0 ?
The solutions to the equation (9-λ)*(4-λ)=0 are λ=9,λ=4
Find the zeros of (9-λ)*(4-λ)=0
The zeros of (9-λ)*(4-λ)=0 are λ=9,λ=4