因式分解 p^2-6-q(p^2-6)^2

解答

因式分解

p^{2} - 6 - q (p^{2} - 6)^{2}

(p^{2} - 6) (1 - p^{2} q + 6 q)

求解步骤

p^{2} - 6 - q (p^{2} - 6)^{2}

因式分解出通项

(p^{2} - 6) : (p^{2} - 6) (1 - q (p^{2} - 6))

= (p^{2} - 6) (1 - q (p^{2} - 6))

展开

1 - q (p^{2} - 6) : 1 - p^{2} q + 6 q

= (p^{2} - 6) (1 - p^{2} q + 6 q)

f a c t or \frac{4}{5} x^{2} - \frac{64}{5} x^{4}

9 < 3 x + 12 \leq 12

(x + 2) 2 - 4 = 0

(\frac{1}{8})^{x - 6} < 6 4^{x - 1}

8 - 2 x \leq 2 - x